破题,不看提示硬控我五个小时,最后参考区间法做出
with median as (
select grade,number,he,add_up,med,lag(add_up)over(order by grade) la
from (select grade,number,sum(number)over() he,sum(number)over(order by grade) add_up,sum(number)over()/2 med
from class_grade) t1
)
select grade
from median
where med between la and add_up

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