用二分法解,注意mid的取值和left和right的关系

class Solution:
    def findPeakElement(self , nums: List[int]) -> int:
        # write code here
        num_length = len(nums)
        left = 0
        right = num_length - 1
        while left < right:
            mid = int((left + right) / 2)
            if nums[mid] < nums[mid + 1]:
                left = mid + 1
            else:
                right = mid 
        return right