排序加贪心,看了一圈评论区和题解,我这个应该是唯一正确的,评论区里举的其他楼主的解法不能pass的反例,我这个都可以pass。
解法是参考@aglangyue的,但参考的解法也有bug,我这里fix了。大家放心享用!

import java.io.*;
import java.util.*;

public class Main {
    private static int read(StreamTokenizer st) throws IOException{
        st.nextToken();
        return (int) st.nval;
    }
    public static void main(String[] args) throws IOException{
        StreamTokenizer st = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
        //读取N
        int N = read(st);
        //读取数组
        int[] arr = new int[N];
        for(int i=0; i<N; i++){
            arr[i] = read(st);
        }
        //数组排序
        Arrays.sort(arr);
        //贪心
        int pre=-1, size=0, cnt=0;
        int idx = 0;
        while(idx<N){
            if(size==0){
                pre = arr[idx++];
                size=1;
            }else if(size==1){
                int gap=arr[idx]-pre;
                if(gap>10 && gap<=20){
                    cnt++;
                    size=0;
                    idx++;
                }else if(gap>20){
                    cnt += 2;
                    size=1;
                    pre = arr[idx++];
                }else{
                    pre = arr[idx++];
                    size = 2;
                }
            }else{
                int gap=arr[idx]-pre;
                if(gap>10){
                    cnt++;
                    pre = arr[idx++];
                    size=1;
                }else{
                    size=0;
                    idx++;
                }
            }
        }
        if(size==1){
            cnt +=2;
        }else if(size==2){
            cnt +=1;
        }

        System.out.println(cnt);
    }
}