select
        concat('2023-',every_month) time,
        sum(t_amount) total
from (
    select
        substr(t.t_time,6,2) every_month,
        t.t_amount
    from 
            trade as t
    left join 
            customer as c
    on 
            t.t_cus = c.c_id
    where
            t.t_cus = 101
    and 
            year(t.t_time) = '2023'
    and
            t.t_type = 1
)a
group by 
        every_month
order by 
        every_month