题解 | #数字翻转#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

// 翻转一个字符串类型的数字
function rev(strNum) {
    // parseInt 去掉前导 0
    let changeStr = parseInt(strNum, 10).toString()
    // 翻转整个数
    changeStr = changeStr.split('').reverse().join('')
    // 返回一个 Number 类型的数
    return  parseInt(changeStr, 10)
}

void async function () {
    // Write your code here
    while(line = await readline()){
        let tokens = line.split(' ');
        let a = parseInt(tokens[0]);
        let b = parseInt(tokens[1]);
        console.log(rev(rev(a) + rev(b)))
    }
}()