题解 | #鸡兔同笼#

#include <iostream>
using namespace std;

int main() {
    int n;
    while (cin >> n) {
        if (n % 2) cout << 0 << " " << 0 << endl;
        else {
            int min = 0, max = 0;
            if (n % 4) min = n / 4 + (n % 4) / 2; //兔和鸡都有
            else min = n / 4;
            max = n / 2;//全是鸡时取最大
            cout << min << " " << max << endl;
        }
    }
    return 0;
}