答案:
SELECT emp_no,salary, CASE WHEN @salary=s.salary THEN @rank WHEN @salary:=s.salary THEN @rank:=@rank+1 END as t_rank from salaries s,(SELECT @rank:=0,@salary:=NULL) a ORDER BY salary DESC;
答案:
SELECT emp_no,salary, CASE WHEN @salary=s.salary THEN @rank WHEN @salary:=s.salary THEN @rank:=@rank+1 END as t_rank from salaries s,(SELECT @rank:=0,@salary:=NULL) a ORDER BY salary DESC;