# 查询每个部门中绩效得分高于部门平均绩效得分的员工信息
with
t1 as(
select
employee_id,
department_name,
performance_score,
avg(performance_score)over(partition by department_name) as davg
from
employee_projects left join department_info using(employee_id)
)
,
t2 as(
select
employee_id,
department_name,
performance_score
from
t1
where
performance_score>davg
order by
employee_id
)
select * from t2

京公网安备 11010502036488号