题解 | #日期累加#

#include <climits>
#include <iostream>
using namespace std;
int days[] = {
    0,31,28,31,30,31,30,31,31,30,31,30,31
};
int Get_yearMonthDay(int year,int month)
{
    int day = days[month];
    month==2 &&
    (year%4==0 && year%100!=0 || year%400==0) &&
    day++;
    return day;
}
class Date
{
public:
    int _year;
    int _month;
    int _day;
    Date(int year=0, int month=0, int day=0):
    _year(year),_month(month),_day(day){
    }
    Date& operator+(int day)
    {
        _day += day;
        while(_day > Get_yearMonthDay(_year,_month))
        {
            _day -= Get_yearMonthDay(_year,_month);
             _month++;
            if(_month == 13)
            {
                _month = 1;
                _year++;
            }
        }
        return *this;
    }
    void show()
    {
        cout<<_year<<"-";
        if(_month<10)
            cout<<"0"<<_month<<"-";
        else
            cout<<_month<<"-";
        if(_day<10)
            cout<<"0"<<_day<<endl;
        else
            cout<<_day<<endl;
    }
};


int main() {
    int n,y,m,d,t;
    cin>>n;
    while (n--) { // 注意 while 处理多个 case
        cin >> y >> m >> d >> t;
        Date D(y,m,d);
        D+t;
        D.show();
    }
}
// 64 位输出请用 printf("%lld")