思路:非常经典的最大化最小值问题,用二分解决。不过题目没明确说明是最大化最小值,需要分析一下。如果没有学过这种二分题型的同学可以学习一下

代码:

import sys
input = lambda: sys.stdin.readline().strip()

import math
inf = 10 ** 18

def I():
    return input()

def II():
    return int(input())

def MII():
    return map(int, input().split())

def GMI():
    return map(lambda x: int(x) - 1, input().split())

def LI():
    return input().split()

def LII():
    return list(map(int, input().split()))

def LFI():
    return list(map(float, input().split()))

fmax = lambda x, y: x if x > y else y
fmin = lambda x, y: x if x < y else y
isqrt = lambda x: int(math.sqrt(x))

'''

'''

def solve():
    n, k = MII()
    a = LII()
    
    def check(mid):
        cnt = 0
        for i in range(n):
            cnt += a[i] // mid
        return cnt >= k
    
    l, r = 1, 10 ** 9
    while l <= r:
        mid = (l + r) >> 1
        if check(mid):
            l = mid + 1
        else:
            r = mid - 1   
    print(r)

t = 1
# t = II()
for _ in range(t):
    solve()