题解 | 计算一年中的第几天

import sys
def dijitian(y,m,d):
    tg=[0,31,28,31,30,31,30,31,31,30,31,30,31,0]
    if (y%4==0 and y%100!=0) or y%400==0:
        tg[2]=29
        tian=sum(tg[1:m])+d
    else:
        tian=sum(tg[1:m])+d
    return tian
for line in sys.stdin:
    y,m,d=map(int,line.split())
    print(dijitian(y,m,d))