select u.device_id, u.university, sum(if(qpd.result is not null,1,0)) as question_cnt, #使用if函数最简洁 sum(if(qpd.result ='right',1,0)) as right_question_cnt from user_profile as u join question_practice_detail as qpd on u.device_id= qpd.device_id where university='复旦大学' and`date` like '2021-08%' group by u.device_id #按用户聚集