题解 | 不要三句号的歪

#include <stdio.h>
#include <string.h>

int main() {
    char s[21];
    scanf("%s",s);
    int count = 0;
    long long int num_1 = 0;
    long long int num_2 = 0;
    for(int i = 0;i<strlen(s);i++)
    {
        if(s[i] == ',')
        break;
        num_1 = (s[i] - '0')+num_1 * 10;
    }
    for(int j = 0;j<strlen(s);j++)
    {
        if(s[j]==',')
        count ++;
        if (count == 3) 
        {
            count ++;
            continue;
        }
        if (count == 4 )
        {
            num_2 = (s[j] - '0') + num_2 * 10;         
        }
        
    }
    printf("%lld",num_2-num_1-2);
    return 0;
}