import java.util.Scanner;
import java.util.TreeSet;
public class Main {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scanner=new Scanner(System.in);
int q=scanner.nextInt();
TreeSet<Integer> set=new TreeSet<>();
for (int i = 0; i < q; i++) {
int op=scanner.nextInt();
int x=scanner.nextInt();
if(op==1) {
if(!set.add(x)) {
System.out.println("Already Exist");
}
}else if(op==2) {
if(set.isEmpty()) {
System.out.println("Empty");
}else {
if(set.contains(x)) {
set.remove(x);
System.out.println(x);
}else {
Integer a1=set.lower(x);
Integer a2=set.higher(x);
if(a1==null||a2==null) {
set.remove(a1==null?a2:a1);
System.out.println(a1==null?a2:a1);
}else {
long d1=(long)x-a1;
long d2=(long)a2-x;
if(d1<=d2) {
set.remove(a1);
System.out.println(a1);
}else {
set.remove(a2);
System.out.println(a2);
}
}
}
}
}
}
}
}
这一题我后面一直是10个案例过9个,问了下Ai,原来是当前后距离相等时,要求返回值更小的,这一点我那个时候没有注意到



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