题解 | #吃糖果#

#include <bits/stdc++.h>

using namespace std;

int main() {
    int N;//N块巧克力
    int dp[21] = {0};
    dp[1] = 1;
    dp[2] = 2;
    for (int i = 3; i <= 20; ++i) {
        dp[i] = dp[i - 1] + dp[i - 2];
    }
    while (scanf("%d", &N) != EOF) {
        printf("%d\n", dp[N]);
    }
    return 0;
}