题解 | #零钱兑换#

#include <stdio.h>

int main() {
    int n, total = 0;
    scanf("%d", &n);
    
    for(int i = 0; i <= n; i++) {
        for(int j = 0; j <= n / 2; j++) {
            for (int z = 0; z <= n / 5; z++) {
                if(i + 2 * j + 5 * z == n) {
                    total++;
                }
            }
        }
    }
    printf("%d\n", total);
    
    return 0;
}