select o.id, o.is_group_buy, c.name client_name from order_info o left join client c on o.client_id=c.id where datediff(date,'2025-10-15')>0 and product_name in ('C++','Java','Python') and status='completed' and o.user_id in ( select user_id from order_info where datediff(date,'2025-10-15')>0 and product_name in ('C++','Java','Python') and status='completed' group by user_id having count(*)>1 ) order by o.id
- 注意观察两个表
- order_info中有client_id 等于0的情况 对应团购,另外一个表中没有这个id
- 所以只需要以order_info作为连接标准去连接另外一个表就行