题解 | 小店的经营分析

#include <iostream>
using namespace std;

int main() {
    int N;
    cin>>N;
    int *P = new int [N];
    int L;
    int R;
    int count = 0;
    for(int i = 0; i < N; ++i)
        cin>>P[i];
    cin>>L>>R;
    for(int i = 0; i < N; ++i)
        {
            int sum = 0;
            for(int j = i; j < N; ++j){
                sum += P[j];
                if(sum >= L && sum <= R)
                    count++;
            }
        }
    cout<<count;
}
// 64 位输出请用 printf("%lld")