二分思想

function solve( a ) {
    // write code here
//     二分思想,如果存在重复子串m的话 2 * m < = a.length
//     逐步递减 m 直到0
    let  maxLen = Math.floor(a.length / 2);
    while(maxLen > 0){
        let start = 0;
        while(start <= a.length - maxLen * 2){
//      判断数组是否相同,相同直接返回,否则索引左移动
            if(a.slice(start, start + maxLen) ===
               a.slice(start + maxLen, start + maxLen * 2)
              ){
               return maxLen * 2;
               }
            start++;
        }
//     减少长度,再次寻找
        maxLen--;
    }
    return maxLen;
}