C Mu函数
题目地址:
基本思路:
先筛出莫比乌斯函数值,然后我们能发现结果存在循环节,
所以找到循环节就好了。
参考代码:
#pragma GCC optimize(2) #pragma GCC optimize(3) #include <bits/stdc++.h> using namespace std; #define IO std::ios::sync_with_stdio(false); cin.tie(0) #define int long long #define ull unsigned long long #define SZ(x) ((int)(x).size()) #define all(x) (x).begin(), (x).end() #define rep(i, l, r) for (int i = l; i <= r; i++) #define per(i, l, r) for (int i = l; i >= r; i--) #define mset(s, _) memset(s, _, sizeof(s)) #define pb push_back #define pii pair <int, int> #define mp(a, b) make_pair(a, b) #define INF 0x3f3f3f3f inline int read() { int x = 0, neg = 1; char op = getchar(); while (!isdigit(op)) { if (op == '-') neg = -1; op = getchar(); } while (isdigit(op)) { x = 10 * x + op - '0'; op = getchar(); } return neg * x; } inline void print(int x) { if (x < 0) { putchar('-'); x = -x; } if (x >= 10) print(x / 10); putchar(x % 10 + '0'); } const int maxn = 1e7 + 10; int prime[maxn], mu[maxn], pcnt; bool vis[maxn]; void init() { mu[1] = 1; for (int i = 2; i < maxn; i++) { if (!vis[i]) { prime[++pcnt] = i; mu[i] = -1; } for (int j = 1; i * prime[j] < maxn; j++) { vis[i * prime[j]] = true; if (i % prime[j] == 0) { mu[i * prime[j]] = 0; break; } else mu[i * prime[j]] = -mu[i]; } } } int n,k; signed main() { IO; int t; cin >> t; init(); while (t--) { cin >> n >> k; vector<int> v; map<int, int> memo; int now = n; while (!memo[now]) { v.pb(now); memo[now] = 1; now = now + mu[now]; } int j; for (int i = 0; i < SZ(v); i++) if (v[i] == now) { j = i; break; } vector<int> v1; for (int i = j; i < SZ(v); i++) v1.push_back(v[i]); if (k < v.size()) cout << v[k] << '\n'; else cout << v1[(k - v.size()) % v1.size()] << '\n'; } return 0; }