C Mu函数
题目地址:
基本思路:
先筛出莫比乌斯函数值,然后我们能发现结果存在循环节,
所以找到循环节就好了。
参考代码:
#pragma GCC optimize(2)
#pragma GCC optimize(3)
#include <bits/stdc++.h>
using namespace std;
#define IO std::ios::sync_with_stdio(false); cin.tie(0)
#define int long long
#define ull unsigned long long
#define SZ(x) ((int)(x).size())
#define all(x) (x).begin(), (x).end()
#define rep(i, l, r) for (int i = l; i <= r; i++)
#define per(i, l, r) for (int i = l; i >= r; i--)
#define mset(s, _) memset(s, _, sizeof(s))
#define pb push_back
#define pii pair <int, int>
#define mp(a, b) make_pair(a, b)
#define INF 0x3f3f3f3f
inline int read() {
int x = 0, neg = 1; char op = getchar();
while (!isdigit(op)) { if (op == '-') neg = -1; op = getchar(); }
while (isdigit(op)) { x = 10 * x + op - '0'; op = getchar(); }
return neg * x;
}
inline void print(int x) {
if (x < 0) { putchar('-'); x = -x; }
if (x >= 10) print(x / 10);
putchar(x % 10 + '0');
}
const int maxn = 1e7 + 10;
int prime[maxn], mu[maxn], pcnt;
bool vis[maxn];
void init() {
mu[1] = 1;
for (int i = 2; i < maxn; i++) {
if (!vis[i]) {
prime[++pcnt] = i;
mu[i] = -1;
}
for (int j = 1; i * prime[j] < maxn; j++) {
vis[i * prime[j]] = true;
if (i % prime[j] == 0) {
mu[i * prime[j]] = 0;
break;
} else mu[i * prime[j]] = -mu[i];
}
}
}
int n,k;
signed main() {
IO;
int t;
cin >> t;
init();
while (t--) {
cin >> n >> k;
vector<int> v;
map<int, int> memo;
int now = n;
while (!memo[now]) {
v.pb(now);
memo[now] = 1;
now = now + mu[now];
}
int j;
for (int i = 0; i < SZ(v); i++) if (v[i] == now) { j = i; break; }
vector<int> v1;
for (int i = j; i < SZ(v); i++) v1.push_back(v[i]);
if (k < v.size()) cout << v[k] << '\n';
else cout << v1[(k - v.size()) % v1.size()] << '\n';
}
return 0;
}
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