https://leetcode.com/problems/candy/description/

There are N children standing in a line. Each child is assigned a rating value.

You are giving candies to these children subjected to the following requirements:

  • Each child must have at least one candy.
  • Children with a higher rating get more candies than their neighbors.

What is the minimum candies you must give?

字面意思就是一行人分糖果，如果一个人比旁边的人得分多，那么必须也比旁边的人糖果多，问最少需要糖果数量

问题就出在，如果和旁边的人得分一样，那么这个人得多少糖果呢？

这个问题纠结了我好久啊，各种办法都行不通。

举个例子 22输出2 221输出4

整个方向跑偏了

为什么要纠结这个问题呢

只要两个方向都满足题目要求的就好了啊QAQ

根本没有必要还得算基于最优的结果整体平移了多少

题面其实可以理解为：

遇到比当前位置大的，就加一，不要管其他大小比较的

p.s.发现一个好东西vector<int>val(ratings.size(),1);和accumulate(val.begin(),val.end(),0);

class Solution {
public:
    int candy(vector<int> &ratings) {
        if(ratings.size()<=1) return ratings.size();
        vector<int>val(ratings.size(),1);
        for(int i=1;i<ratings.size();i++)
            if(ratings[i]>ratings[i-1])
                val[i]=val[i-1]+1;
        for(int i=ratings.size()-2;i>=0;i--)
            if(ratings[i]>ratings[i+1]&&val[i]<=val[i+1])
                val[i]=val[i+1]+1;
        return accumulate(val.begin(),val.end(),0);
    }
};