使用递归,判断所有的点机器人是否可达即可
public class Solution {
public int movingCount(int threshold, int rows, int cols)
{
int[][] flag = new int[rows][cols]; /*记录已经走过的点*/
return helper(0,0,rows,cols,flag,threshold);
}
public int helper(int i, int j, int rows, int cols, int[][] flag, int threshold){
if(i < 0 || i >= rows || j < 0 || j >= cols || flag[i][j] == 1 || numSum(i)+numSum(j) > threshold)
return 0;
flag[i][j] = 1;
return helper(i+1,j,rows,cols,flag,threshold)+helper(i-1,j,rows,cols,flag,threshold)+
helper(i,j+1,rows,cols,flag,threshold)+helper(i,j-1,rows,cols,flag,threshold)+1;
}
// 计算坐标的数位和
public int numSum(int num){
int sum = 0;
while(num > 0){
sum += num%10;
num /= 10;
}
return sum;
}
}

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