1.翻转二叉树
思路:递归
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* invertTree(TreeNode* root) { if(root==nullptr) return root; TreeNode* left=invertTree(root->left); TreeNode* right=invertTree(root->right);//递归左右子树 root->left=right; root->right=left;//交换 return root; } };