1.翻转二叉树
思路:递归
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
if(root==nullptr) return root;
TreeNode* left=invertTree(root->left);
TreeNode* right=invertTree(root->right);//递归左右子树
root->left=right;
root->right=left;//交换
return root;
}
};
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