题解 | #求最小公倍数#

int main(void) {
    int m;
    int n;
    int min = 0;
    int i = 0;
    int j = 1;
    while(~scanf("%d %d", &m, &n)) {
        min = m > n ? n : m;
        for(i = min; i <= m*n && !(i%m == 0 && i%n == 0); i = (j++)*min) {
            ;
        }
        printf("%d\n", i);
    }
    
}