题解 | 时间转换

#include<bits/stdc++.h>
using namespace std;
int main(){
    int second,a,b,c;
    cin>>second;
    a=second/3600;
    b=(second%3600)/60;
    c=(second%3600)%60;
    cout<<a<<" "<<b<<" "<<c;
    return 0;

}