思路:整体来说就是构造出A、B数组,然后把B数组的元素异或起来。对于构造A数组来说,直接根据题意模拟即可;对于构建B数组来说,首先要注意d | i表示d去整除i,而不是i去整除d,这里我开始就弄错了,然后就可以用埃式筛来构建B数组了。简单来说,埃式筛就是两层for循环,外层i的步长为1,内层j的步长为i,主要是用于筛质数,这里是筛对应的倍数
代码:
import sys
input = lambda: sys.stdin.readline().strip()
import math
inf = 10 ** 18
def I():
return input()
def II():
return int(input())
def MII():
return map(int, input().split())
def GMI():
return map(lambda x: int(x) - 1, input().split())
def LI():
return input().split()
def LII():
return list(map(int, input().split()))
def LFI():
return list(map(float, input().split()))
fmax = lambda x, y: x if x > y else y
fmin = lambda x, y: x if x < y else y
isqrt = lambda x: int(math.sqrt(x))
'''
'''
def solve():
n, a1, m = LII()
A = [0] * (n + 1)
A[1] = a1
for i in range(2, n + 1):
A[i] = (A[i - 1] + 7 * i) % m
B = [0] * (n + 1)
for d in range(1, n + 1):
for i in range(d, n + 1, d):
B[i] += A[d]
ans = 0
for i in range(1, n + 1):
ans ^= B[i]
print(ans)
t = 1
# t = II()
for _ in range(t):
solve()

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