select
grade
from
(
select
grade,
sum(number) over (
order by
grade asc
) as ascnum,
sum(number) over (
order by
grade desc
) as descnum,
(
select
sum(number)
from
class_grade
) as total
from
class_grade
) sub
where
ascnum >= total / 2
and descnum >= total / 2
order by
grade asc;



京公网安备 11010502036488号