题解 | 删除字符串中出现次数最少的字符

package main

import (
    "fmt"
)

func main() {
    var keyword []byte
    fmt.Scan(&keyword)
    countMap := make(map[byte]int)
    // 得出每个字母的出现次数
    for _, letter := range keyword {
        countMap[letter] = countMap[letter] + 1
    }
    // 得出最小的出现次数
    minCount := len(keyword)
    for _, count := range countMap {
        if count < minCount {
            minCount = count
        }
    }
    // 打印出险次数大于最小次数的字母
    for _, letter := range keyword {
        if countMap[letter] > minCount {
            fmt.Print(string(letter))
        }
    }
}