SELECT b.qdiff, COUNT(if(b.result = 'right', 1, null)) / COUNT(1) AS correct_rate FROM (SELECT device_id FROM user_profile WHERE university = '浙江大学') AS a INNER JOIN (SELECT qpd.device_id, qpd.question_id, qpd.result, qd.difficult_level AS qdiff FROM question_practice_detail AS qpd INNER JOIN question_detail AS qd ON qd.question_id = qpd.question_id) AS b ON a.device_id = b.device_id GROUP BY b.qdiff ORDER BY correct_rate;