题解 | #字符串合并处理#

'''
解题思路：
1、奇数排序：L[::2] = sorted(L[::2])，偶数排序：L[1::2] = sorted(L[1::2])，按字符的acsii实际值排序
2、构造一个函数实现字符翻转: 输入字符有其它超过0-9，a-f，A-F的其它字符,如g-z,G-Z。其它字符不变，满足条件的字符大写变小写
3、十六进制->十进制，二进制->十六进制，采用字典实现
'''
def f(s):
    if ('0'<= s <= '9') or ('a'<= s <= 'f') or ('A'<= s <= 'F'):
        if s.isupper():
            s = s.lower()
        dic1 = {'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,
                '8':8,'9':9,'a':10,'b':11,'c':12,'d':13,'e':14,'f':15}
        dic2 = {'0000':'0','0001':'1','0010':'2','0011':'3',
                '0100':'4','0101':'5','0110':'6','0111':'7',
                '1000':'8','1001':'9','1010':'A','1011':'B',
                '1100':'C','1101':'D','1110':'E','1111':'F'}
        t = bin(dic1[s])
        t = t[2:]
        t = str(t)
        t = t.zfill(4)
        t = t[::-1]
        t = dic2[t]
        return t
    else:
        return s
#---------------------------------------------------------------
while 1:
    try:
        L1,L2 = input().strip().split()
        L = list(L1+L2)
        L[::2] = sorted(L[::2])
        L[1::2] = sorted(L[1::2])
        tmp = ''
        for s in L:
            tmp = tmp+f(s)
        print(tmp)
    except:
        break