select u.id,u.name, c.grade_num
from(
select a.user_id,a.grade_num
from (select user_id,sum(grade_num) grade_num from grade_info group by user_id) a
where grade_num=(
select sum(grade_num) grade_num
from grade_info
group by user_id
order by grade_num desc
limit 1
)
group by a.user_id
order by a.user_id) c
left join
user u
on c.user_id = u.id
order by u.id
- 找到最大值
- 筛选得到id和分数
- 然后连接表获得名字

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