select u.id,u.name, c.grade_num from( select a.user_id,a.grade_num from (select user_id,sum(grade_num) grade_num from grade_info group by user_id) a where grade_num=( select sum(grade_num) grade_num from grade_info group by user_id order by grade_num desc limit 1 ) group by a.user_id order by a.user_id) c left join user u on c.user_id = u.id order by u.id
- 找到最大值
- 筛选得到id和分数
- 然后连接表获得名字