题解 | #密码强度等级#

Python3 解法，巧用ASCII

	while True:
    try:
        s = input()
        sc = 0
        # 密码长度
        if len(s) <= 4:
            sc += 5
        elif len(s) <= 7:
            sc += 10
        else:
            sc += 25

        # 字母
        isu = 0
        isl = 0
        for i in s:
            if "A" <= i <= "Z":
                isu = 1
                break
        for i in s:
            if "a" <= i <= "z":
                isl = 1
                break
        sc += 10 * (isu + isl)

        # 数字
        count1 = 0
        for i in s:
            if "0" <= i <= "9":
                count1 = count1 + 1
        if count1 == 1:
            sc += 10
        elif count1 > 1:
            sc +=  20
        else:
            sc = sc

        # 符号
        fh = '!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~'
        count2 = 0
        for i in s:
            if i in fh:
                count2 += 1
        if count2 == 1:
            sc += 10
        elif count2 > 1:
            sc += 25
        else:
            sc = sc

        # 奖励
        if isu + isl == 2 and count1 >= 1 and count2 >= 1:
            sc += 5
        elif isu + isl > 1 and count1 >= 1 and count2 >= 1:
            sc += 3
        elif isu + isl > 1 and count1 >= 1:
            sc += 2
        if sc >= 90:
            print("VERY_SECURE")
        elif sc >= 80:
            print("SECURE")
        elif sc >= 70:
            print("VERY_STRONG")
        elif sc >= 60:
            print("STRONG")
        elif sc >= 50:
            print("AVERAGE")
        elif sc >= 25:
            print("WEAK")
        elif sc >= 0:
            print("VERY_WEAK")
    except:
        break