select
user_id
,min(date) first_buy_date
,count(*) cnt
from order_info
where user_id in ( # 先找出来满足条件的用户id
select user_id
from order_info
where date > '2025-10-15'
and product_name in ('C++', 'Java', 'Python')
and status = 'completed'
group by 1
having count(*) >= 2
)
and date > '2025-10-15'
and product_name in ('C++', 'Java', 'Python')
and status = 'completed'
group by 1
order by 1;
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