select user_id ,min(date) first_buy_date ,count(*) cnt from order_info where user_id in ( # 先找出来满足条件的用户id select user_id from order_info where date > '2025-10-15' and product_name in ('C++', 'Java', 'Python') and status = 'completed' group by 1 having count(*) >= 2 ) and date > '2025-10-15' and product_name in ('C++', 'Java', 'Python') and status = 'completed' group by 1 order by 1;