select exam_id, start_month, month_cnt, sum(month_cnt) over (partition by exam_id order by start_month ) cum_exam_cnt from ( select exam_id, DATE_FORMAT(start_time,'%Y%m') start_month, count(exam_id) month_cnt from exam_record group by exam_id,DATE_FORMAT(start_time,'%Y%m') ) a order by exam_id,start_month
窗口函数基础用法,
sum(month_cnt) over (partition by exam_id order by start_month ) cum_exam_cnt
表示按照exam_id为维度的滑动窗口计算month_cnt的总值