select
exam_id,
start_month,
month_cnt,
sum(month_cnt) over (partition by exam_id order by start_month ) cum_exam_cnt
from
(
select
exam_id,
DATE_FORMAT(start_time,'%Y%m') start_month,
count(exam_id) month_cnt
from exam_record
group by exam_id,DATE_FORMAT(start_time,'%Y%m')
) a
order by exam_id,start_month
窗口函数基础用法,
sum(month_cnt) over (partition by exam_id order by start_month ) cum_exam_cnt
表示按照exam_id为维度的滑动窗口计算month_cnt的总值

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