题解 | #零钱兑换#

#include <iostream>
using namespace std;
int main(){
    
    int n;
    cin>>n;
    int count = 0;
    for(int i = 0;i<=n;i++){
        for(int j = 0;j<=n;j++){
            for(int k = 0;k<=n;k++){
                if(n==i + 2*j + 5*k){
                    count+=1;
                }
            }
        }
    }
    cout<<count;
    
    
    
    return 0;
}