题解 | A-B≠C

#include <iostream>
using namespace std;
const double EPS=1e-9;
int main(){
    double a,b,c;
    cin>>a>>b>>c;
    if(abs(a-b-c)<EPS)cout<<"YES\n";
    else cout<<"NO\n";
    return 0;
}
// 64 位输出请用 printf("%lld")