思路要保持清晰
几个条件分函数写
纯粹考察代码能力
point:substr和find

#include<iostream>
#include<string>
using namespace std;

bool checkchar(string str)//包括大小写字母.数字.其它符号,以上四种至少三种
{
    int i0 = 0, i1 = 0, i2 = 0, i3 = 0;
    for (int i = 0; i < str.size(); i++)
    {
        if (str[i] >= 'a' && str[i] <= 'z')
        {
            i0 = 1;
        }
        else if (str[i] >= 'A' && str[i] <= 'Z')
        {
            i1 = 1;
        }
        else if (str[i] >= '0' && str[i] <= '9')
        {
            i2 = 1;
        }
        else {
            i3 = 1;
        }
    }
    if (i0 + i1 + i2 + i3 >= 3)
    {
        return true;
    }
    else
    {
        return false;
    }
}
bool checksubstr(string str)
{
    int len = str.size();
    for (int i = 0; i < len - 3; i++)
    {
        string s = str.substr(i, 3);
        if (str.find(s, i + 3) != str.npos)  //找到重复
        {
            return false;
        }
    }
    return true;
}

int main()
{
    string str;
    //循环处理
    while (cin >> str)
    {
        if (str.size()>8&&checksubstr(str)&&checkchar(str))
        {
            cout << "OK" << endl;
        }
        else
        {
            cout << "NG" << endl;
        }
    }
    return 0;
}