题解 | 矩阵转置

n,m=map(int,input().split())
l=[]
l2=[]
for i in  range(n):
    seq=list(map(int,input().split()))
    l.extend(seq)
for i in range(m):
    for j in range(n):
      l2.append(l[i+j*m])
    print(*l2[i*n:(i+1)*n])