SELECT device_id, university, gpa
FROM (
SELECT *,
dense_rank() over(
partition by university 
order by gpa) AS rankn
FROM user_profile
) AS a
WHERE a.rankn = 1;

筛选gpa最低的:先根据gpa排序,再筛出gpq最低的

  1. 根据gpa排序:
SELECT *,
dense_rank() over(
  partition by university 
  order by gpa) AS rankn 
  FROM user_profile) AS a

再用select嵌套一下