先与(1010 0xaaaaaaaa)//16进制的1010/，然后0x55555555 左移，即可交换成功

`#include using namespace std; int main() { int x; cin >> x; int a, b; a = x & (0xaaaaaaaa);//32位的101010... b = x & (0x55555555);//32位的010101... x = (a>>1) ^ (b<<1);a右移一位，b左移一位 cout << x;
return 0; }