题解 | 日期差值

#include <iostream>
using namespace std;

int main() {
    int a,b;
    while (scanf("%d %d",&a,&b)!=EOF) { // 注意 while 处理多个 case
        int y1,mon1,d1,y2,mon2,d2;
        y1=a/10000;mon1=(a/100)%100;d1=a%100;
        y2=b/10000;mon2=(b/100)%100;d2=b%100;
        int i=1;
        for(i=1;!(y1==y2&&mon1==mon2&&d1==d2);i++){
            bool flag=false;//flag=0表示不是闰年
            
                d1++;
                if(y1%4==0&&y1%100!=0)flag=true;
                else if(y1%400==0)flag=true;
                else flag=false;
                if(mon1==2){
                    if(flag==true&&d1>29){
                            mon1=3;d1=1;
                    }
                    if(flag==false&&d1>28){
                            mon1=3;d1=1;                        
                    }
                }
                if(d1>31 &&(mon1==1||mon1==3||mon1==5||mon1==7||mon1==8||mon1==10||mon1==12)){
                    d1=1;
                    mon1++;
                }
                if(d1>30&&(mon1==4||mon1==6||mon1==9||mon1==11)){
                    d1=1;
                    mon1++;
                }
                if(mon1>12){
                    mon1=1;
                    y1++;
                }            
        }
        printf("%d\n",i);
    }
}