//先乘去掉小数点再计算
#include <iostream>
using namespace std;

int main() {
    double a,b,c;
    scanf("%lf %lf %lf",&a,&b,&c);
    if((long long)(a*10000000)-(long long)(b*10000000)==(long long)(c*10000000))cout<<"YES"<<endl;
    else cout<<"NO"<<endl;
    return 0;
 
}
// 64 位输出请用 printf("%lld")