#anta # every pay methode number distribution desc with t1 as (select ul.*,pi.price,pi.product_name, case when ul.pay_method='' and ul.step='select' then 'error' else ul.pay_method end as method_with_dirty from user_client_log ul left join product_info pi on ul.product_id=pi.product_id where pi.product_name="anta") select t1.method_with_dirty,count(*) as number from t1 group by t1.method_with_dirty having t1.method_with_dirty!="" order by number desc
本题两个注意事项:
1.有两种脏数据需要处理 1.题目明确指出的 “”且 ul.step = select的脏数据,此类脏数据才会标为error,计入结果
2.其余脏数据照样得剔除。



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