解法1：三重循环

#include <iostream>
#include <cstdio>
using namespace std;
int main(){
    int a, b, c;
    for(a = 1; a <= 9; a++)
        for(b = 1; b <= 9; b++)
            for(c = 0; c <= 9; c++){
                int x = a * 100 + b * 10 + c;
                int y = b * 100 + c * 10 + c;
                if(x + y == 532)
                    printf("%d %d %d\n", a, b, c); 
            }
    return 0;
}