题解 | 删除链表中重复的结点

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param pHead ListNode类 
# @return ListNode类
#
class Solution:
    def deleteDuplication(self , pHead: ListNode) -> ListNode:
        # write code here
        dummy = ListNode(0)
        dummy.next = pHead#头置哑节点，确保头节点与后续节点同样可操作
        cur, pHead = pHead, dummy#前一节点，当前节点
        while cur and cur.next:
            if cur.val!=cur.next.val:#当前节点与后一节点不重复
                pHead, cur = cur, cur.next#两个节点各前进一位
                continue#跳出本次循环
            while cur.next and cur.val==cur.next.val:#当前节点与后一节点重复
                cur = cur.next#找到该段循环链表的最后一个节点
            pHead.next, cur = cur.next, cur.next#节点拼接
        return dummy.next