题解 | 汽水瓶

import java.util.Scanner;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        /*
         * 三个空汽水瓶可以换一瓶汽水 总共有n个空汽水瓶 0=<n<=100 当n=0时代表输入结束*/
        Scanner scanner = new Scanner(System.in);
        List<Integer> emptySodaBottle = new ArrayList<>();
        while (scanner.hasNextLine()) {
            String exit = scanner.nextLine();
            if (exit.equals("0")) {
                break;
            }
            emptySodaBottle.add(Integer.parseInt(exit));
        }
        for (int i = 0; i < emptySodaBottle.size(); i++) {
            int emptySodeBottleNumber = emptySodaBottle.get(i);
            System.out.println(maximumAmountOfSodaToDrink(emptySodeBottleNumber));
        }
    }

    private static int maximumAmountOfSodaToDrink(int emptySodeBottleNumber) {
        int num = 0; //可以喝的数量
        int discuss = 0;//商的数量
        int remainder = 0;//余数的数量
//10 3+1+1  4 2
        if (emptySodeBottleNumber >= 3) {
            discuss = emptySodeBottleNumber / 3;
            num += discuss;
            remainder = emptySodeBottleNumber % 3;
            emptySodeBottleNumber = discuss + remainder;
            num += maximumAmountOfSodaToDrink(emptySodeBottleNumber);
        } else if (emptySodeBottleNumber == 2) {
            num++;
        }
        return num;
    }
}