题解 | #特殊乘法#

#include "stdio.h"
using namespace std;

int main(){
    int num1,num2;
    while (scanf("%d%d",&num1,&num2)!=EOF) {
        int count1=0,count2=0;//count1为num1的位数，count2为num2的位数
        int array1[12],array2[12];
    while (num1 > 0) {
        array1[count1] = num1%10;
        num1 = num1/10;
        ++count1;
    }
    while (num2 > 0) {
        array2[count2] = num2%10;
        num2 = num2/10;
        ++count2;
    }
    int sum = 0;
    for(int i = 0;i<count1;++i){
        for(int j = 0;j<count2;++j){
            sum = sum + array1[i]*array2[j];
        }
    }
    printf("%d\n",sum);
    }
}