#include <bits/stdc++.h> using namespace std; const int maxn = 1000 + 10; int n,m; int a[maxn]; int main(){ cin >> n; for(int i = 0;i < n;i ++){ cin >> a[i]; } sort(a,a + n); cin >> m; while(m --){ int x; cin >> x; int position = lower_bound(a,a + n,x) - a; // 地址,数组下标 if(position != n && a[position] == x){ cout << "YES" << endl; }else{ cout << "NO" << endl; } } return 0; }