题解 | 时间转换

#include <iostream>
using namespace std;

int main()
{
    long seconds;
    
    cin >> seconds;
    
    int h, m, s;
    h = seconds / (60 * 60);
    m = (seconds % (60 * 60)) / 60;
    s = seconds % 60;
    
    cout << h << " " << m << " " << s << endl;
    
    return 0;
}